Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A particle is moving along the
axis with its coordinate with time
given by
. Another particle is moving along the
-axis with its coordinate as a function of time given by
. At
, the speed of the second particle as measured in the frame of the first particle is given as
. Then
(in
is
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: First, find the velocity functions of both particles by differentiating their position functions with respect to time.
Step 2: Substitute t = 1s into both velocity functions:
Step 3: The relative speed of the second particle as measured in the frame of the first particle is given by v = v2 - v1. Therefore:
Concluding that the speed of the second particle in the frame of the first particle at t = 1s is -26 m/s.
- For the first particle: x(t) = 10 + 8t - 3t^2
Thus, v1(t) = dx/dt = 8 - 6t - For the second particle: y(t) = 5 - 8t^3
Thus, v2(t) = dy/dt = -24t^2
Step 2: Substitute t = 1s into both velocity functions:
- v1(1) = 8 - 6(1) = 2 m/s
- v2(1) = -24(1)^2 = -24 m/s
Step 3: The relative speed of the second particle as measured in the frame of the first particle is given by v = v2 - v1. Therefore:
- v = -24 - 2 = -26 m/s
Concluding that the speed of the second particle in the frame of the first particle at t = 1s is -26 m/s.
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